if you're sitting in a room with forty people in it, what are the chances that two of those people have the same birthday?... 11% ? 22% 75% hmmmmmm
what thinkest tho, oh great matematicians?
The Birthday Paradox
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The Birthday Paradox
"Integrity" and "integer" both contain a Latin root meaning "whole; complete." The root sense, then, is that people may be said to be acting with integrity when their beliefs, words, and actions have a sense of unity or wholeness.
Now If I wasnt so lazy Id take out my Analytical Techniques handbook and give you the formulae... Its quite easy, but sooo much work
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Slasher : Former member of www.PCFormat.co.za
I have reached the end of my near 5 year forum life. Farewell good days...
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wouldnt it be like 1/365 * 1/365 ... x 40 ?
I hated ATE , so not going to go into the book hunt now... dont even know where it is anymore...
I hated ATE , so not going to go into the book hunt now... dont even know where it is anymore...
My BF2142 Stats:
Slasher : Former member of www.PCFormat.co.za
I have reached the end of my near 5 year forum life. Farewell good days...
slasher (at) webmail (dot) co (dot) za
Slasher : Former member of www.PCFormat.co.za
I have reached the end of my near 5 year forum life. Farewell good days...
slasher (at) webmail (dot) co (dot) za
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Well if you considder that there are 365 possible birthdays then the odds for any 2 people to share the same birthday would probably be 365 to 1. However if you have 40 people the odds should increase by the amount of people devided by 2. Thus I would say 365 to 20 or 5.48%.
Just when I got the hang of life they changed the rules.
What are the odds then of all 40 people sharing that birthday y0da?
I dont quite understand the logic...
There is a standard formuale for throwing a dice and getting same number twice... This is just a 365 sided dicce (Unless you count leap years) and you roll 40 times...
I dont quite understand the logic...
There is a standard formuale for throwing a dice and getting same number twice... This is just a 365 sided dicce (Unless you count leap years) and you roll 40 times...
My BF2142 Stats:
Slasher : Former member of www.PCFormat.co.za
I have reached the end of my near 5 year forum life. Farewell good days...
slasher (at) webmail (dot) co (dot) za
Slasher : Former member of www.PCFormat.co.za
I have reached the end of my near 5 year forum life. Farewell good days...
slasher (at) webmail (dot) co (dot) za
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Well if you take in consideration the fact that 2 people have a 1 in 365 chance to share the same birthday then 4 people would have a 2 in 365 chance and 40 people a 20 in 365 chance. This is just pseudo logic of course and not based on any formulas.
Edit - The above is for 2 people in a crow of 40. To find the chance for all 40 to share the same birthday I would guess you could devide the odds by the number of people. So it would then be 365 to 1/40 or 0.007%
Edit - The above is for 2 people in a crow of 40. To find the chance for all 40 to share the same birthday I would guess you could devide the odds by the number of people. So it would then be 365 to 1/40 or 0.007%
Just when I got the hang of life they changed the rules.